حمّل تطبيق منهاجي الجديد

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  أتحقق من فهمي

أتحقق من فهمي

تبسيط المقادير الأسية

أتحقق من فهمي صفحة (24):

أجد قيمة كل مما يأتي في أبسط صورة:

a) begin mathsize 20px style 32 to the power of 1 fifth end exponent end style = 2

b) begin mathsize 20px style 9 to the power of 5 over 2 end exponent end style = 243

c) begin mathsize 20px style left parenthesis 16 right parenthesis to the power of negative 5 over 4 end exponent end style = begin mathsize 20px style 1 over 32 end style

أتحقق من فهمي صفحة (26):

أجد قيمة كل مما يأتي في أبسط صورة:

a) begin mathsize 20px style a to the power of 2 over 3 end exponent end style x begin mathsize 20px style a to the power of negative 3 over 7 end exponent end style =  begin mathsize 20px style root index 21 of a to the power of 5 end root end style

b) begin mathsize 20px style left parenthesis x to the power of 5 over 2 end exponent right parenthesis to the power of negative 7 over 5 end exponent end style = begin mathsize 20px style fraction numerator 1 over denominator square root of x to the power of 7 end root end fraction end style

c) begin mathsize 20px style left parenthesis y space x space z right parenthesis to the power of 5 over 4 end exponent end style = begin mathsize 20px style y to the power of 5 over 4 end exponent end style x begin mathsize 20px style z to the power of 5 over 4 end exponent end style

d) begin mathsize 20px style x to the power of begin display style 9 over 2 end style end exponent over x to the power of 8 over 5 end exponent end style = begin mathsize 20px style root index 10 of x to the power of 29 end root end style

e) begin mathsize 20px style left parenthesis x over y squared right parenthesis to the power of negative 3 over 2 end exponent end style = begin mathsize 20px style fraction numerator y cubed over denominator square root of x cubed end root end fraction end style

f) begin mathsize 20px style fraction numerator fifth root of x squared end root over denominator root index 7 of x cubed end root end fraction end style = begin mathsize 20px style fraction numerator 1 over denominator root index 35 of x end fraction end style

أتحقق من فهمي صفحة (27):

أكتب كلاً مما يأتي في أبسط صورة، علما بأن جميع المتغيرات أعداد حقيقية موجبة:

a) begin mathsize 20px style fraction numerator 9 x to the power of negative begin display style 3 over 4 end style end exponent space y over denominator 3 x to the power of begin display style 7 over 2 end style end exponent space y to the power of negative begin display style 5 over 3 end style end exponent space end fraction end style = begin mathsize 20px style fraction numerator 3 cube root of y to the power of 8 end root over denominator fourth root of x to the power of 17 end root end fraction end style

b) begin mathsize 20px style fraction numerator left parenthesis 125 y to the power of negative begin display style 9 over 2 end style end exponent right parenthesis left parenthesis 10 x y to the power of begin display style 10 over 3 end style end exponent right parenthesis over denominator left parenthesis 5 x to the power of 5 over 2 end exponent y right parenthesis left parenthesis y to the power of negative 3 over 7 end exponent right parenthesis end fraction end style = begin mathsize 20px style fraction numerator 250 over denominator square root of x cubed end root space x space root index 42 of y to the power of 73 end root end fraction end style

c) begin mathsize 20px style fourth root of 16 x to the power of 18 space y to the power of 22 end root end style = 2begin mathsize 20px style square root of x to the power of 9 space y to the power of 11 end root end style

إعداد : شبكة منهاجي التعليمية

18 / 09 / 2024

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