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أتدرب وأحل المسائل

الاقترانات المثلثية

أجد قيم الاقترانات المثلثية الستة للزاوية Ɵ في كلّ ممّا يأتي: 

1)

الاقترانات المثلثية

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell x equals square root of 81 minus 9 end root equals square root of 72 equals 6 square root of 2 end cell row blank cell s i n invisible function application theta equals 1 third comma space of 1em c o s invisible function application theta equals fraction numerator 2 square root of 2 over denominator 3 end fraction comma space of 1em t a n invisible function application theta equals fraction numerator 1 over denominator 2 square root of 2 end fraction end cell row blank cell c s c invisible function application theta equals 3 comma space of 1em s e c invisible function application theta equals fraction numerator 3 over denominator 2 square root of 2 end fraction comma space of 1em c o t invisible function application theta equals 2 square root of 2 end cell end table end style

2)

الاقترانات المثلثية

begin mathsize 20px style table attributes columnalign left left columnspacing 1em end attributes row cell x equals square root of left parenthesis 18 right parenthesis squared minus left parenthesis 9 right parenthesis squared end root equals 4 square root of 14 end cell blank row cell s i n invisible function application theta equals fraction numerator 2 square root of 14 over denominator 9 end fraction space comma end cell cell c o s invisible function application theta equals 5 over 9 comma space of 1em t a n invisible function application theta equals fraction numerator 2 square root of 14 over denominator 5 end fraction end cell row cell c s c invisible function application theta equals fraction numerator 9 over denominator 2 square root of 14 end fraction space comma end cell cell s e c invisible function application theta equals 9 over 5 comma space of 1em c o t invisible function application theta equals fraction numerator 5 over denominator 2 square root of 14 end fraction end cell end table end style

3)

الاقترانات المثلثية

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell x equals square root of left parenthesis 26 right parenthesis squared minus left parenthesis 14 right parenthesis squared end root equals 4 square root of 30 end cell row blank cell s i n invisible function application theta equals fraction numerator 2 square root of 30 over denominator 13 end fraction comma space of 1em c o s invisible function application theta equals 7 over 13 comma space of 1em t a n invisible function application theta equals fraction numerator 2 square root of 30 over denominator 7 end fraction end cell row blank cell c s c invisible function application theta equals fraction numerator 13 over denominator 2 square root of 30 end fraction comma space of 1em s e c invisible function application theta equals 13 over 7 comma space of 1em c o t invisible function application theta equals fraction numerator 7 over denominator 2 square root of 30 end fraction end cell end table end style

 

تقع النقطة المعطاة في كلّ مما يأتي على ضلع انتهاء الزاوية Ɵ المرسومة في الوضع القياسي. أجد قيم الاقترانات المثلثية الستة للزاوية Ɵ .

4) (-12, 5)

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell r equals square root of 144 plus 25 end root equals 13 end cell row blank cell s i n invisible function application theta equals 5 over 13 comma space of 1em c o s invisible function application theta equals negative 12 over 13 comma space of 1em t a n invisible function application theta equals negative 5 over 12 end cell row blank cell c s c invisible function application theta equals 13 over 5 comma space of 1em s e c invisible function application theta equals negative 13 over 12 comma space of 1em c o t invisible function application theta equals negative 12 over 5 end cell end table end style

5) (3, -3)

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell r equals square root of 9 plus 9 end root equals 3 square root of 2 end cell row blank cell s i n invisible function application theta equals negative fraction numerator 1 over denominator square root of 2 end fraction comma space of 1em c o s invisible function application theta equals fraction numerator 1 over denominator square root of 2 end fraction comma space of 1em t a n invisible function application theta equals negative 1 end cell row blank cell c s c invisible function application theta equals negative square root of 2 comma space of 1em s e c invisible function application theta equals square root of 2 comma space of 1em c o t invisible function application theta equals negative 1 end cell end table end style

6) (-2, -5)

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell r equals square root of 4 plus 25 end root equals square root of 29 end cell row blank cell s i n invisible function application theta equals negative fraction numerator 5 over denominator square root of 29 end fraction comma space of 1em c o s invisible function application theta equals negative fraction numerator 2 over denominator square root of 29 end fraction comma space of 1em t a n invisible function application theta equals 5 over 2 end cell row blank cell c s c invisible function application theta equals negative fraction numerator square root of 29 over denominator 5 end fraction comma space of 1em s e c invisible function application theta equals negative fraction numerator square root of 29 over denominator 2 end fraction comma space of 1em c o t invisible function application theta equals 2 over 5 end cell end table end style

7) (3, 7)

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell r equals square root of 9 plus 49 end root equals square root of 58 end cell row blank cell s i n invisible function application theta equals fraction numerator 7 over denominator square root of 58 end fraction comma space of 1em c o s invisible function application theta equals fraction numerator 3 over denominator square root of 58 end fraction comma space of 1em t a n invisible function application theta equals 7 over 3 end cell row blank cell c s c invisible function application theta equals fraction numerator square root of 58 over denominator 7 end fraction comma space of 1em s e c invisible function application theta equals fraction numerator square root of 58 over denominator 3 end fraction comma space of 1em c o t invisible function application theta equals 3 over 7 end cell end table end style

أجد قيمة كلّ ممّا يأتي: 

8) sec 135o

begin mathsize 20px style s e c invisible function application 135 to the power of ring operator equals negative s e c invisible function application 45 to the power of ring operator equals negative square root of 2 end style

9) begin mathsize 20px style tan invisible function application space left parenthesis negative fraction numerator 3 pi over denominator 4 end fraction right parenthesis end style

begin mathsize 20px style tan minus fraction numerator 3 pi over denominator 4 end fraction equals negative tan invisible function application space fraction numerator 3 pi over denominator 4 end fraction equals 1 end style

10) begin mathsize 20px style cot space left parenthesis fraction numerator 8 straight pi over denominator 3 end fraction right parenthesis end style

begin mathsize 20px style cot invisible function application space fraction numerator 8 pi over denominator 3 end fraction equals cot invisible function application space fraction numerator 2 pi over denominator 3 end fraction equals negative fraction numerator 1 over denominator square root of 3 end fraction end style

11) begin mathsize 20px style cos space left parenthesis fraction numerator 7 pi over denominator 4 end fraction right parenthesis end style

begin mathsize 20px style cos invisible function application space fraction numerator 7 pi over denominator 4 end fraction equals cos invisible function application space pi over 4 equals fraction numerator 1 over denominator square root of 2 end fraction end style

12) begin mathsize 20px style sec space left parenthesis fraction numerator 15 straight pi over denominator 4 end fraction right parenthesis end style  

begin mathsize 20px style sec invisible function application space fraction numerator 15 pi over denominator 4 end fraction equals sec invisible function application space pi over 4 equals square root of 2 end style

13) csc (-630o)

begin mathsize 20px style csc minus 630 to the power of ring operator equals csc invisible function application space 90 to the power of ring operator equals 1 end style

14) tan 7π

begin mathsize 20px style tan invisible function application space 7 pi equals tan invisible function application space pi equals 0 end style

15) begin mathsize 20px style sin space left parenthesis negative fraction numerator 2 pi over denominator 3 end fraction right parenthesis end style

begin mathsize 20px style sin minus fraction numerator 2 pi over denominator 3 end fraction equals negative sin invisible function application space pi over 3 equals negative fraction numerator square root of 3 over denominator 2 end fraction end style

 

أجد قيمة كل من الاقترانات المثلثية الخمسة المتبقية للزاوية Ɵ في كلّ ممّا يأتي: 

16) begin mathsize 20px style cos invisible function application space theta equals negative 7 over 12 space comma space tan invisible function application space theta greater than 0 end style

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell r equals square root of 144 minus 49 end root equals square root of 95 end cell row blank cell s i n invisible function application theta equals negative fraction numerator square root of 95 over denominator 12 end fraction comma space of 1em t a n invisible function application theta equals fraction numerator square root of 95 over denominator 7 end fraction end cell row blank cell c s c invisible function application theta equals negative fraction numerator 12 over denominator square root of 95 end fraction comma space of 1em s e c invisible function application theta equals negative 12 over 7 comma space of 1em c o t invisible function application theta equals fraction numerator 7 over denominator square root of 95 end fraction end cell end table end style

17) begin mathsize 20px style sec invisible function application space theta equals 5 space comma space sin invisible function application space theta less than 0 end style

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell r equals square root of 25 minus 1 end root equals square root of 24 end cell row blank cell s i n invisible function application theta equals negative fraction numerator square root of 24 over denominator 5 end fraction comma space of 1em t a n invisible function application theta equals negative square root of 24 end cell row blank cell c s c invisible function application theta equals negative fraction numerator 5 over denominator square root of 24 end fraction comma space of 1em c o s invisible function application theta equals 1 fifth comma space of 1em c o t invisible function application theta equals negative fraction numerator 1 over denominator square root of 24 end fraction end cell end table end style

18) begin mathsize 20px style cot invisible function application space theta equals 1 fourth space comma space sin invisible function application space theta less than 0 end style

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell r equals square root of 16 plus 1 end root equals square root of 17 end cell row blank cell s i n invisible function application theta equals negative fraction numerator 4 over denominator square root of 17 end fraction comma t a n invisible function application theta equals 4 comma c s c invisible function application theta equals negative fraction numerator square root of 17 over denominator 4 end fraction comma c o s invisible function application theta equals negative fraction numerator 1 over denominator square root of 17 end fraction comma s e c invisible function application theta equals negative square root of 17 end cell end table end style

19) begin mathsize 20px style csc invisible function application space theta equals 2 space comma space c os invisible function application space theta greater than 0 end style

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell r equals square root of 4 minus 1 end root equals square root of 3 end cell row blank cell s i n invisible function application theta equals 1 half comma space of 1em t a n invisible function application theta equals fraction numerator 1 over denominator square root of 3 end fraction comma c o t invisible function application theta equals square root of 3 comma space of 1em c o s invisible function application theta equals fraction numerator square root of 3 over denominator 2 end fraction comma space of 1em s e c invisible function application theta equals fraction numerator 2 over denominator square root of 3 end fraction end cell end table end style

 

(20) بكرة: يمثل الاقتران: y = 20 + sin (10t) الارتفاع الرأسي عن سطح الأرض بالسنتيمترات لسِنّ بكرة دراجة هوائية بعد t ثانية من بدء حركة الدارجة. أجد الارتفاع الرأسي لسِنّ البكرة بعد 2.5 ثانية من بدء حركة الدرّاجة.

begin mathsize 20px style y equals 20 plus s i n invisible function application space 10 left parenthesis 2.5 right parenthesis equals 20 plus s i n invisible function application space 25 almost equal to 19.87 cm end style

 

إذا كان: cos begin mathsize 20px style straight pi over 12 end style = 0.966 لأقرب ثلاث منازل عشرية فأستعمل هذه الحقيقة لإيجاد قيمة كلّ ممّا يأتي:

21) cos begin mathsize 20px style fraction numerator 13 straight pi over denominator 12 end fraction end style

begin mathsize 20px style c o s invisible function application space fraction numerator 13 pi over denominator 12 end fraction equals negative c o s invisible function application space pi over 12 equals negative 0.966 end style

22) cos begin mathsize 20px style fraction numerator 11 straight pi over denominator 12 end fraction end style 

begin mathsize 20px style cos invisible function application space fraction numerator 11 pi over denominator 12 end fraction equals negative cos invisible function application space pi over 12 equals negative 0.966 end style

23) cos begin mathsize 20px style fraction numerator negative straight pi over denominator 12 end fraction end style

begin mathsize 20px style cos invisible function application fraction numerator negative pi over denominator 12 end fraction equals cos invisible function application pi over 12 equals 0.966 end style

24) cos begin mathsize 20px style fraction numerator 23 straight pi over denominator 12 end fraction end style 

begin mathsize 20px style cos invisible function application space fraction numerator 23 pi over denominator 12 end fraction equals cos invisible function application space pi over 12 equals 0.966 end style

 

أجد قيمة كلّ ممّا يأتي: 

25) begin mathsize 20px style left parenthesis cos invisible function application space fraction numerator 3 pi over denominator 4 end fraction right parenthesis squared plus left parenthesis sin invisible function application space fraction numerator 4 pi over denominator 3 end fraction right parenthesis squared plus left parenthesis cos invisible function application space fraction numerator 5 pi over denominator 4 end fraction right parenthesis squared end style

begin mathsize 20px style left parenthesis c o s invisible function application space fraction numerator 3 pi over denominator 4 end fraction right parenthesis squared plus left parenthesis s i n invisible function application space fraction numerator 4 pi over denominator 3 end fraction right parenthesis squared plus left parenthesis c o s invisible function application space fraction numerator 5 pi over denominator 4 end fraction right parenthesis squared equals 1 half plus 9 over 4 plus 1 half equals 7 over 4 end style

26) begin mathsize 20px style sin invisible function application space pi over 3 minus sin invisible function application space fraction numerator 2 pi over denominator 3 end fraction plus sin invisible function application space pi minus sin invisible function application space fraction numerator 4 pi over denominator 3 end fraction plus sin invisible function application space fraction numerator 5 pi over denominator 3 end fraction minus sin invisible function application space 2 pi end style

begin mathsize 20px style sin invisible function application space pi over 3 minus sin invisible function application space fraction numerator 2 pi over denominator 3 end fraction plus sin invisible function application space pi minus sin invisible function application space fraction numerator 4 pi over denominator 3 end fraction plus sin invisible function application space fraction numerator 5 pi over denominator 3 end fraction minus sin invisible function application space 2 pi equals 0 end style

 

يبين الشكل المجاور قطاعاً دائرياً، طول نصف قطره  r، وطول قوسه 2r . إذا كانت مساحة الجزء المظلل من القطاع 24 cm2 ، فأجد كلاً ممّا يأتي:

قطاع دائري

(27) طول نصف قطر القطاع.

نفترض Ɵ زاوية القطاع.

begin mathsize 20px style table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row blank cell l equals r theta not stretchy rightwards arrow 2 r equals r theta not stretchy rightwards arrow theta equals 2 end cell row blank cell A equals 1 half r squared theta minus 1 half r squared s i n invisible function application space theta not stretchy rightwards arrow 24 equals 1 half r squared left parenthesis 2 right parenthesis minus 1 half r squared s i n invisible function application space 2 end cell row blank cell not stretchy rightwards arrow r equals square root of fraction numerator 48 over denominator 2 minus s i n invisible function application 2 end fraction end root almost equal to 6.6 cm end cell end table end style

(28) محيط الجزء المظلل.

نفترض طول الضلع الثالث في المثلث الأبيض يساوي h

نجد عن طريق قانون جيب التمام أو بإنزال عمود من رأس المثلث المتطابق الضلعين على القاعدة.

فنجد h = 2r sin 1

محيط الشكل المظلل:

begin mathsize 20px style P equals 2 r plus h equals 2 r plus 2 r s i n invisible function application space 1 almost equal to 24.3 space cm end style

 

أجد قيمة كلّ ممّا يأتي (إن وجدت): 

29) begin mathsize 20px style sin to the power of negative 1 end exponent invisible function application space left parenthesis negative fraction numerator square root of 3 over denominator 2 end fraction right parenthesis end style

begin mathsize 20px style s i n to the power of negative 1 end exponent invisible function application space left parenthesis negative fraction numerator square root of 3 over denominator 2 end fraction right parenthesis equals negative pi over 3 end style

30) tan-1 (-1)

begin mathsize 20px style tan to the power of negative 1 end exponent invisible function application space left parenthesis negative 1 right parenthesis equals negative pi over 4 end style

31) begin mathsize 20px style tan to the power of negative 1 end exponent invisible function application space left parenthesis square root of 3 right parenthesis end style

begin mathsize 20px style tan to the power of negative 1 end exponent invisible function application space left parenthesis square root of 3 right parenthesis equals pi over 3 end style

32) cos-1 (2)

begin mathsize 20px style cos to the power of negative 1 end exponent invisible function application space left parenthesis fraction numerator square root of 2 over denominator 2 end fraction right parenthesis equals pi over 4 end style

إعداد : شبكة منهاجي التعليمية

25 / 02 / 2023

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